Simplify:

${\frac{(6x^3y^{-4})^{-2}}{(3x^2y^{-2})^{-3}}}$

The correct answer is ${\dfrac{3}{4}}y^2$

${\dfrac{(6x^3y^{-4})^{-2}}{(3x^2y^{-2})^{-3}}}$

${\dfrac{(3x^2y^{-2})^{3}}{(6x^3y^{-4})^{2}}}$

${\dfrac{27 (x^6y^{-6})}{36 (x^{6}y^{-8})}}$

${\dfrac{3 y^{-6+8}}{4}}$

${\dfrac{3}{4}}y^2$